Charles VIII

30 Jun 1470 JUL    CAL
saturday JUL
lat 47° 24' 59" | N 0°59' E
Amboise
---------------------------------
natal 2h 35' 0"
lmt 2h 31' 4"
tu 2h 31' 4"
tsn 21h 41' 53"
---------------------------------
timezone
Equation of time 0h 3' 51"
ΔT 0h 3' 51"

source https://www.astro.com/astro-databank/Charles_VIII,_King_of_France

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Histoire généalogique des souverains de la France : ses gouvernements de Hugues Capet à l'année 1896 par Alfred Franklin, p. 40, Paris, 1896

CHARLES VIII Dit l'Affable.

Fils de Louis XI et de Charlotte de Savoie. Né au château d'Amboise le samedi 30 juin 1470 (1), vers trois heures du malin. Roi le 30 août 1483, sous la régence de sa sœur Anne de Beaujeu. Mon à Amboise le 7 avril 1498.

Femme :.

Anne de Bretagne, fille et héritière-de François II, duc de Bretagne. Née à Nantes le 20janvier 1470. Mariée le 0 décembre 1401. Veuve le 7 avril 1498. Remariée le 8 janvier 1400 au roi Louis XII. Morte à Blois le 0 janvier 1514.

Enfants :
Charles-Orland, né au château de Montils-les-Tours le 8 septembre 1402. Mort le 6 décembre 1495.

Charles, né à Montils-les-Tours le 8 septembre 1496.
Mort le 2 octobre de la même année.

François, né et mort en 1407.

Anne, morte jeune.

(1) « Le samedi,derrenier jour de juing 1470, environ deux et trois heures de matin, la royne acoucha au château d'Amboise d’un beau filz. » (Jean de Royes, Chronique, édit. Mandrot, p. 241.)
---------------------------------------------------------------

CHARLES VIII Says the Affable.

Son of Louis XI and Charlotte of Savoy. Born at the Château d'Amboise on Saturday June 30, 1470 (1), around three o'clock in the morning. King on August 30, 1483, under the regency of his sister Anne de Beaujeu. Mon at Amboise on April 7, 1498.
Women :.
Anne de Bretagne, daughter and heiress of François II, Duke of Brittany. Born in Nantes on January 20, 1470. Married on December 0, 1401. Widowed on April 7, 1498. Remarried on January 8, 1400 to King Louis XII. Died at Blois on January 0, 1514.
Children :
Charles-Orland, born in the castle of Montils-les-Tours on September 8, 1402. Died on December 6, 1495.
Charles, born in Montils-les-Tours on September 8, 1496.
Died on October 2 of the same year.
François, born and died in 1407.
Anne, who died young.
(1) “On Saturday, the last day of June 1470, around two and three o'clock in the morning, the queen gave birth to a beautiful son at the Château d'Amboise. (Jean de Royes, Chronicle, ed. Mandrot, p. 241.)

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quoted in Junctinus, Speculum astrologiae, p. 707 but no hour and wrong date

zodiacal natal chart

۞ KADHKHUDǠH		BIRTH	1470
n YEARS	Δ EQU	EQUATION OF TIME	corr, Y
(Z) 30,92	± 1,05	(+) + 0h 3m 51,6s	0,06
conserve same years - ( Y)	32,42		0,97
	(z) : zodiacal – (m) mundane	even	year
(M) 27,082	29,11	28 / corr. 29,97	1498
HYLEG	ASC	84,06	GEM
ALCHOCODEN	MO	122,44	LEO
		MA - no parall	(Z :141,62)
ALCHO RAYS ASC, MC, POF, SYG (y)	(Z) ALCHO RAYS PLANETS (y)	(z & m) ALCHO PARALLELS (y)
		# (z) MO / SA -2,08 -
	(M) ALCHO RAYS PLANETS (y)
note : angular house → greater years for I and X – middle for IV and VII	VE 60 MO: 1 minus alcho dy (2,05)	dyH : dynamic house, The principle of dynamic astrological houses is the same as for the zodiac. I remind you that a planet located in the last five degrees of a sign is considered to be part of the next sign (provided it is not retrograde). For houses, it is the opposite which, logically, must be understood: a planet located in the first five degrees of a house is considered in the previous house (even if it is retrograde): Indeed, it is necessary consider the "flow" of the primum mobile that seems to move the whole sky. See Ali-Kayyat, Judgments of Nativities for Kadhkhudah peregrine – cap, 3
(P)eregrine – (D)etrimental – (F)all – (Ru)ler – (E)xalt – (Ori)entation – (R)etrograde - (T)rip - (Fa)ce - (te)rm	nocturnal chart	EXTRA
ORIGIN OF HYLEG	ASC	Ω -163,35 /
ASC (1) - dy2		JU : +0
CAN (f)		VE : +8
|Dor 0 |AL-QAB 0 |PTO 0 (0)		MA : x-0,33
alternative hyleg : SU / diurnal dom : ME / nocturnal dom : SA		SA : x-1
-
		SYNTHESIS FROM DOROTHEUS ALCABITIUS AND PTOLEMY BONATTI
ORIGIN OF ALCHOCODEN	ŽMO	SU | P | 0 | dyH1 | BONATTI 0
dign / no dign-- /ray by ASC no aspect° MO /min λ : VE / min orb :na		MO | P | 0 | dyH3
no dignity ; try another point for alcho (alcho. dominance na)		ASC | (- | -) 1 | - (MO waxing | POF in 12)
house / 3 = cad : minor years (25 Y corrected from Al-Kayyat tab if VII (0,9) or IV (0,8))		POF | () 0 | - | dyH12 --| BONATTI 0/not waning, = 0
		SYG (NM) | 0 | - | dyH1
condition list : P 0,08- D 1- F 1 || Ru 0 || E 1- Ori 1 - R 1 - besieged 1 - (1 ok - 0,8 bad)
conserve same years - ( Y)
P -
TRAD, ALMUTEN OF NATIVITY (OMAR, IBN EZRA)
ME
term 3 tri 2 rul 0 exn 0 fac 2
su 2 mo 0 asc 1 syg 2 pof 2
DOM : JU
LILLY ALMUTEN OF NATIVITY
Lilly ALM : MA
ALGOL conj - (zodiacal)
under sun bean’s : --
besieged : -- | - nearby rays :--
chart nocturnal | waxing (conjunctional) moon
TRAD ALMUDEBIT
JU

First, when the zodiacal chart is examined, it appears that the hyleg is the ASC and the alchocoden MA. MA is opposed to MC and VE is in conjunction with ASC. In fact in the zodiac, there is a trine MA-VE but it mutates into a square on the mundane theme. The ASC is linked to MO by a mundane sextil. MO is at the last degrees of house II (succedent) and is therefore in a cadent house.

mundane natal chart

So by considering the house system according to the mundane scheme, we take ASC as hyleg and MO as alchocoden (especially since the chart is nocturnal). Certainly it turns out that the alchocoden is weak, being P and in a cadent house.

Hyleg – alchocoden

ZODIACAL
In our research, we hypothesized that the mundane chart alone should be considered; also we must base on the aspects taken in the sem-iarcs the research of the degrees likely to be considered in the duration of the life.
In the case of Charles VIII we have the table above which allows us to estimate the breakdown of aspects between the different planets and the alchocoden.

When considering a theme, the first thing is to observe whether it is diurnal or nocturnal. In the case of Charles VIII, it is NOCTURNAL.
In this case, the first point to check is MO. If  MO is well disposed, she can claim 1st stage to be HYLEG.

MO is P and therefore seems weak, with a dignity score of -5,
Moreover, when we look for the dignities that appear in the zodiacal inscription of MO, we find none.
We'll see later what we get when we search for mundane dignities.
Now that we doubt to take MO as hyleg, we are left with the choice of ASC and that of POF. It is the way in which is laid out MO which will indicate the choice to us. If MO is waxing, we take ASC for hyleg ; if MO is waning, we take POF for hyleg,

It turns out that MO is waxing; so we will take ASC,

Now we must look for the alchocoden: it is the planet which has the maximum dignity with regard to the hyleg and which exchanges a Ptolemaic aspect with the hyleg.
we don't observe any aspect or dignity with ASC in the ZODIACAL system
At the same time, it appears that MA has  dignity over ASC.
So we have two possibilités with our hypothesis : first choose ASC for hyleg with no alchocoden ; second choose the MUNDANE system and try to find another couple of hyleg/alchocoden,

MUNDANE
Now we have to think about the hyleg to find: MO is not suitable; the rule is then in a nocturnal theme to reconsider first the case of SU,
In the mundane theme with REGIOMONTANUS domification, we find a triplicity dignity :MA with a sextil for SU
MA is cad
however, MA is located within 5° of the point (IC). In this case, we are led to increase its value which, otherwise, would be 15 Y.
To do this, the procedure is not unequivocal but one of the most logical seems to me to be the one mentioned by Auger Ferrier in Jugements astronomiques sur les nativités, Rouen, 1583 (pp, 39-51 and notably pp, 43-48)
the years of life are identified for the cad and ang houses relative to the alchocoden.
cad = 15 Y
ang = 66 Y
we take the difference = 51 Y
take the 1/5 of this difference = 10,2 Y
then take the difference between 5 and the actual position of the point = 3,56 (1,44)
take the rule of three = 7,26 Y
Then we add the cad Y 15 and 7,26 = 22,26 Y
Now, we have to take account of the radix mundane aspects,
SU 60 MA: 9,5   VE 90 MA: -8     minus alcho dy (1,44)

given that ve is close to axis (ASC or MC) at less than 5°, we can add 8 Y
So, Y=   31,76

Primary directions (PM)

DIRECTION : □SU conj MA
---------------------------------
We must take into account an important element: the ascensional difference (DA); it can be observed on the  graph in a dotted line (measured between the horizon and the axis of the pole). This is the difference between Right Ascension (AR) and Oblique Ascension (OA). This is the difference between Right Ascension (AR) and Oblique Ascension (OA). DA is always calculated in absolute value |DA| and it is added or subtracted from 90° (SA = 90° corresponds to a point on the equator cut by the horizon; depending on whether a star approaches or moves away from the line of horizon, SA is > 90° or < 90°, i,e, (+) depending on whether it is diurnal and northern ; or nocturnal and southern ; (-) depending on whether it is diurnal and southern ; or nocturnal and northern.

sin(DA) = -tan(φ)tan(δ)
φ = latitude 47,42 N
δ MA = 15,41 +
DA-MA = 17,45°
δ □SU =3,11 +
DA-□SU =3,39°

We will first use the Placidus system of mundane directions. The simplest system is that of Choisnard-Fomalhaut. First you need to retrieve the data from the SA (semi-arc) and the DM (meridian distance) of the nocturnal point because the altitude of MA is -27,17°. important note: the SA and DM of the two points are always counted diurnal if the first point (here MA) is above the horizon even if the second is below. They are counted nightly if the first point (MA) is below the horizon regardless of the position of the second point.
For DMs, they are counted in AR from the diurnal meridian if the fixed point MA is diurnal, and from the nocturnal meridian if it is nocturnal.

nocturnal meridian MC = 145,47°
AR MA = 144,46°
AR □SU = 172,82°

SA N (d+) MA = 72,55°
DM N  MA = -1,01°

For the  significator  □SU altitude (h) =-34,07°. so :

SA N (δ+) □SU = 86,61°
DM N  □SU = -152,65°

Then we compute Saf/DMf (so : SA f [ 72,55°] / DM f [ -1,01°])

Sa f / DM f =71,75

and the angle x = SAm x DM f/SA f, so : SA m [ 86,61°] x DM f [ -1,01°]/SA f [ 72,55°]

 x = -1,21°

We find the direction by DMm - x, so : DM m [ -152,65°] ± x [-1,21]
We must now have regard to the double ± sign of the last expression; in the case where f (MA) and m (□SU) are on either side of the meridian, the direction arc is obtained by taking the sum (instead of the difference) of the two quantities DMm and x. this is the case here so sign = (-)
the computation of the arc requires, depending on the case, a reduction of 360° (so arc modulo 360°)
---------------------------------
arc D =28,56°
---------------------------------
in the technical sense, It is a direct direction but in the astrological sense, it is a true converse direction since it is an aspect considered as a promissor which goes towards the significator. ; so the m point is an aspect (here □SU) and the f point is a planet or an axis, (here MA)

We can now compute the converse direction : point f is directed towards point m, i.e. the star is directed towards the aspect. This is where the problem of the orientation of the primum mobile arises because it is not concevable to rotate the local sphere in both directions… It does not seem convenient to postulate that the arc of direction is counted in the order of the signs of the zodiac (when it is direct, i.e. when one directs a promissor towards a significator): indeed, the ecliptic has nothing to do with a direction since this one depends only on the diurnal movement ( primum mobile). It is therefore otherwise that we must pass judgment on this.

That time, we compute Sa m / DM m (so : SA m [ 86,61°] / DM f [ -152,65°])

Sa m / DM m =3,17

and the angle x = SA f x DM m/SA m, so : SA f [ 72,55°] x DM m [ -152,65°] / SA m [ 86,61°]

x = -22,91°

We find the direction by DM f - x, so : DM f [ -1,01°] ± x [-22,91°]
We must now have regard to the double ± sign of the last expression; in the case where m (□SU) and f (MA) are on either side of the meridian, the direction arc is obtained by taking the sum (instead of the difference) of the two quantities DM f and x. this is the case here : so, signe = (+)
---------------------------------
arc C =21,9°
---------------------------------
Now we can study the same direction with the Regiomontanus system. To obtain the arc of direction between two signifying points (planets in body, aspect versus planet, planet versus axis) one must find AO (oblique ascent) of f and of m, calculated under the pole of f.
The formulas to use can be found either in the Dictionnaire astrologique of Henri Joseph Gouchon (Dervy Livres, 1937) pp. 266-267, or in his Horoscope annuel simplifié (Dervy, 1973) p.181. Other formulas can be found in Les moyens de pronostic en astrologie, Max Duval (editions traditionnelles, 1986) and Domification et transits (Editions traditionnelles, 1985). We can also cite by André Boudineau : Les bases scientifiques de l’astrologie (Chacornac, 1937) These are references in French but there are many other references in English or German of a less obvious but equally valid use.

First, compute the ascensional difference under f (MA) : cot DAP f = (cot de f x cot lat) / in DM f ± cot DM f, i,e, :  cot (DAP f) = (Cot dec f[15,41°] x Cot Lat [47,42°]) /sin DM f [1,01°] ± cot DM f  [1,01°]

DAPf = 0,23°

We find the pole of f (MA) by formula : tan(pole f) = sin (DAP f) x cot (dec f) i,e, tan(pole f) = tan f [0,43°] x cot f [15,41°]

pole MA regio  =1,57°

(1) We need now the DAP of m (□SU) under the pole of f, sin (DAP m) = tan (pole f) x tan (DEC m), i,e, : (MA) : sin (DAPm/f) = tan [1,57°] x tan [3,11°]

DAP m/f = 0,09°

then we find for the points located in the eastern part of the chart : AO f = AR f± DAP f ; sign (+) if Dec f boreal or sign (–) if Dec f Austral ; so : AO f MA = 144,9° and AO m = AR m ± DAP m ; idem for sign ; so  AO m□SU = 172,91°

---------------------------------
arc D Regio = -28,71°
---------------------------------
We are now going to compute the converse Regiomontanus direction corresponding to the arc  f MA / p □SU

First, compute the ascensional difference under m (□SU) : cot DAPm = (cot dec m x cot lat)/sin DM m ± cot DM m, i,e, :  Cot(DAP m) = (Cot decm[3,11°] x Cot Lat [47,42°]) / Sin DM f [27,35°] ± Cot DM m [27,35°]

DAP m = 1,48°

We find the pole of m (□SU) by formula : Tan(pole m) = Sin (DAP m) x Cot (dec m) i,e, Tan(pole m) = Sin m [178,36°] x Cot m [3,11°]

pole □SU regio  =27,82°

We need now the DAP of f (MA) under the pole of m, Sin (DAP f) = Tan (pole m) x Tan (DEC f), i,e, : (□SU) : Sin (DAP f/m) = Tan[27,81°] x Tan [15,41°]

DAP f/m = 8,36°

then we find for the points located in the eastern part of the chart : AO m = AR m ± DAP m ; sign (+) if Dec m boreal or sign (–) if Dec m Austral ; so : AO m □SU = 174° and AO f = AR f ± DAP f ; idem for sign ; so  AO f MA = 152,82°

---------------------------------
arc C Regio = -21,64°
---------------------------------
H.J. Gouchon [l’Horoscope Annuel simplifié, Dervy, 1973, p, 181-182 and Dictionnaire astrologique, p, 277, 1937-1942, Gouchon ed., 1975, Dervy, but be careful because in DAP's equation, the double sign ± was mistakenly replaced by the sign (-) ] advises to avoid errors, to always place the star A1 (for us f, i.e. SU) in the eastern houses; in fact it is enough to change the registration number of the house based on the transformation (IV-V-VI) -> (X-XI-XII) and (VII-VIII-IX) -> (I-II-III ) to adapt the double sign ± in the calculation of DAP f or DAP m; moreover, this sign must be reversed if |DM| > 90°.

For the Regiomontanus directions, there is another mode of computing, mentioned by Gouchon (Dictionnaire astrologique, op. cit., p. 276) and especially Martin Gansten (Primary directions, pp. 155-157, the Wessex Astrologer, 2009)
This method consists at computing first 3 auxiliary angles before  the pole. It then joins the other method. Contrary to what Gouchon says, I find it easier than the previous one because we avoid the double sign ± in the determination of DAP f.

So, initially, we have A => Tan f = tan dec f [15,41°] / cos DM f [-1,01°]

A = 15,41°

Then : B = Lat [47,42°] + A [-15,41°]

B = 62,83°

And, Tang C = Cot DM f [-1,01°] x Cos B [62,83°] / Cos A [-15,41°]

C = -87,87°

Then, we have Sin pole f = Cos C [-87,87°] x  Sin LG [47,42°]
---------------------------------
So, pole MA regio = 1,57°
---------------------------------
Now go back to (1)

For m □SU; we have : A => Tan m = tan dec m [3,11°] / cos DM m [27,35°]

A = 3,5°

Then : B = Lat [47,42°] + A [-3,5°]

B = 50,92°

And, Tang C = Cot DM m [-152,65°] x Cos B [50,92°] / Cos A [-3,5°]

C = 50,69°

Then, we have Sin pole m = Cos C [50,69°] x  Sin LG [47,42°]
---------------------------------
So, pole □SU regio = 27,81°
---------------------------------
Now go back to (1)

DIRECTION : □SA conj SU
---------------------------------
We must take into account an important element: the ascensional difference (DA); it can be observed on the  graph in a dotted line (measured between the horizon and the axis of the pole). This is the difference between Right Ascension (AR) and Oblique Ascension (OA). This is the difference between Right Ascension (AR) and Oblique Ascension (OA). DA is always calculated in absolute value |DA| and it is added or subtracted from 90° (SA = 90° corresponds to a point on the equator cut by the horizon; depending on whether a star approaches or moves away from the line of horizon, SA is > 90° or < 90°, i,e, (+) depending on whether it is diurnal and northern ; or nocturnal and southern ; (-) depending on whether it is diurnal and southern ; or nocturnal and northern.

sin(DA) = -tan(φ)tan(δ)
φ = latitude 47,42 N
δ SU = 22,51 +
DA-SU = 26,8°
δ □SA =18,03 +
DA-□SA =20,75°

We will first use the Placidus system of mundane directions. The simplest system is that of Choisnard-Fomalhaut. First you need to retrieve the data from the SA (semi-arc) and the DM (meridian distance) of the nocturnal point because the altitude of SU is -12,25°. important note: the SA and DM of the two points are always counted diurnal if the first point (here SU) is above the horizon even if the second is below. They are counted nightly if the first point (SU) is below the horizon regardless of the position of the second point.
For DMs, they are counted in AR from the diurnal meridian if the fixed point SU is diurnal, and from the nocturnal meridian if it is nocturnal.

nocturnal meridian MC = 145,47°
AR SU = 107,69°
AR □SA = 131,54°

SA N (d+) SU = 63,2°
DM N  SU = -37,78°

For the  significator  □SA altitude (h) =-23,36°. so :

SA N (δ+) □SA = 69,25°
DM N  □SA = -13,93°

Then we compute Saf/DMf (so : SA f [ 63,2°] / DM f [ -37,78°])

Sa f / DM f =1,67

and the angle x = SAm x DM f/SA f, so : SA m [ 69,25°] x DM f [ -37,78°]/SA f [ 63,2°]

 x = 41,4°

We find the direction by DMm - x, so : DM m [ -13,93°] ± x [41,4]
We must now have regard to the double ± sign of the last expression; in the case where f (SU) and m (□SA) are on either side of the meridian, the direction arc is obtained by taking the sum (instead of the difference) of the two quantities DMm and x. This is not the case here, so sign = (+)
the computation of the arc requires, depending on the case, a reduction of 360° (so arc modulo 360°)
---------------------------------
arc D =-27,47°
---------------------------------
in the technical sense, It is a direct direction but in the astrological sense, it is a true converse direction since it is an aspect considered as a promissor which goes towards the significator. ; so the m point is an aspect (here □SA) and the f point is a planet or an axis, (here SU)

We can now compute the converse direction : point f is directed towards point m, i.e. the star is directed towards the aspect. This is where the problem of the orientation of the primum mobile arises because it is not concevable to rotate the local sphere in both directions… It does not seem convenient to postulate that the arc of direction is counted in the order of the signs of the zodiac (when it is direct, i.e. when one directs a promissor towards a significator): indeed, the ecliptic has nothing to do with a direction since this one depends only on the diurnal movement ( primum mobile). It is therefore otherwise that we must pass judgment on this.

That time, we compute Sa m / DM m (so : SA m [ 69,25°] / DM f [ -13,93°])

Sa m / DM m =0,42

and the angle x = SA f x DM m/SA m, so : SA f [ 63,2°] x DM m [ -13,93°] / SA m [ 69,25°]

x = 12,71°

We find the direction by DM f - x, so : DM f [ -37,78°] ± x [12,71°]
We must now have regard to the double ± sign of the last expression; in the case where m (□SA) and f (SU) are on either side of the meridian, the direction arc is obtained by taking the sum (instead of the difference) of the two quantities DM f and x. This is not the case here, so sign = (-)
---------------------------------
arc C =25,07°
---------------------------------
Now we can study the same direction with the Regiomontanus system. To obtain the arc of direction between two signifying points (planets in body, aspect versus planet, planet versus axis) one must find AO (oblique ascent) of f and of m, calculated under the pole of f.
The formulas to use can be found either in the Dictionnaire astrologique of Henri Joseph Gouchon (Dervy Livres, 1937) pp. 266-267, or in his Horoscope annuel simplifié (Dervy, 1973) p.181. Other formulas can be found in Les moyens de pronostic en astrologie, Max Duval (editions traditionnelles, 1986) and Domification et transits (Editions traditionnelles, 1985). We can also cite by André Boudineau : Les bases scientifiques de l’astrologie (Chacornac, 1937) These are references in French but there are many other references in English or German of a less obvious but equally valid use.

First, compute the ascensional difference under f (SU) : cot DAP f = (cot de f x cot lat) / in DM f ± cot DM f, i,e, :  cot (DAP f) = (Cot dec f[22,51°] x Cot Lat [47,42°]) /sin DM f [37,78°] ± cot DM f  [37,78°]

DAPf = 11,51°

We find the pole of f (SU) by formula : tan(pole f) = sin (DAP f) x cot (dec f) i,e, tan(pole f) = tan f [23,23°] x cot f [22,51°]

pole SU regio  =43,59°

(1) We need now the DAP of m (□SA) under the pole of f, sin (DAP m) = tan (pole f) x tan (DEC m), i,e, : (SU) : sin (DAPm/f) = tan [43,59°] x tan [18,03°]

DAP m/f = 18,05°

then we find for the points located in the eastern part of the chart : AO f = AR f± DAP f ; sign (+) if Dec f boreal or sign (–) if Dec f Austral ; so : AO f SU = 130,93° and AO m = AR m ± DAP m ; idem for sign ; so  AO m□SA = 149,59°

---------------------------------
arc D Regio = -29,03°
---------------------------------
We are now going to compute the converse Regiomontanus direction corresponding to the arc  f SU / p □SA

First, compute the ascensional difference under m (□SA) : cot DAPm = (cot dec m x cot lat)/sin DM m ± cot DM m, i,e, :  Cot(DAP m) = (Cot decm[18,03°] x Cot Lat [47,42°]) / Sin DM f [166,07°] ± Cot DM m [-13,93°]

DAP m = 176,37°

We find the pole of m (□SA) by formula : Tan(pole m) = Sin (DAP m) x Cot (dec m) i,e, Tan(pole m) = Sin m [7,41°] x Cot m [18,03°]

pole □SA regio  =21,61°

We need now the DAP of f (SU) under the pole of m, Sin (DAP f) = Tan (pole m) x Tan (DEC f), i,e, : (□SA) : Sin (DAP f/m) = Tan[21,6°] x Tan [22,51°]

DAP f/m = 9,45°

then we find for the points located in the eastern part of the chart : AO m = AR m ± DAP m ; sign (+) if Dec m boreal or sign (–) if Dec m Austral ; so : AO m □SA = 139° and AO f = AR f ± DAP f ; idem for sign ; so  AO f SU = 117,14°

---------------------------------
arc C Regio = -25,89°
---------------------------------
H.J. Gouchon [l’Horoscope Annuel simplifié, Dervy, 1973, p, 181-182 and Dictionnaire astrologique, p, 277, 1937-1942, Gouchon ed., 1975, Dervy, but be careful because in DAP's equation, the double sign ± was mistakenly replaced by the sign (-) ] advises to avoid errors, to always place the star A1 (for us f, i.e. SU) in the eastern houses; in fact it is enough to change the registration number of the house based on the transformation (IV-V-VI) -> (X-XI-XII) and (VII-VIII-IX) -> (I-II-III ) to adapt the double sign ± in the calculation of DAP f or DAP m; moreover, this sign must be reversed if |DM| > 90°.

For the Regiomontanus directions, there is another mode of computing, mentioned by Gouchon (Dictionnaire astrologique, op. cit., p. 276) and especially Martin Gansten (Primary directions, pp. 155-157, the Wessex Astrologer, 2009)
This method consists at computing first 3 auxiliary angles before  the pole. It then joins the other method. Contrary to what Gouchon says, I find it easier than the previous one because we avoid the double sign ± in the determination of DAP f.

So, initially, we have A => Tan f = tan dec f [22,51°] / cos DM f [-37,78°]

A = 27,67°

Then : B = Lat [47,42°] + A [-27,67°]

B = 75,09°

And, Tang C = Cot DM f [-37,78°] x Cos B [75,09°] / Cos A [-27,67°]

C = -20,55°

Then, we have Sin pole f = Cos C [-20,55°] x  Sin LG [47,42°]
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So, pole SU regio = 43,59°
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Now go back to (1)

For m □SA; we have : A => Tan m = tan dec m [18,03°] / cos DM m [-13,93°]

A = 18,54°

Then : B = Lat [47,42°] + A [-18,54°]

B = 65,96°

And, Tang C = Cot DM m [-13,93°] x Cos B [65,96°] / Cos A [-18,54°]

C = -60°

Then, we have Sin pole m = Cos C [-60°] x  Sin LG [47,42°]
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So, pole □SA regio = 21,6°
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Now go back to (1)