PRESLEY Elvis

PRESLEY Elvis

(January 8, 1935 – August 16, 1977) was an American singer and actor. Regarded as one of the most significant cultural icons of the 20th century. Presley suffered from a a variant associated with the heart-muscle disease hypertrophic cardiomyopathy. 

8 January 1935 at 04:35 (= 04:35 AM )
Place Tupelo, Mississippi, 34n15, 88w42
Timezone CST h6w (is standard time)

source : https://www.astro.com/astro-databank/Presley,_Elvis

conj SA-MO
MA Detrimental
SU, VE and JU peregrine

Hyleg : ASC
alchocoden : MA

Primary directions

SU conj (m) # MA

	Lat	Dec	AR	MD	SA	HA
SU	-	-22,34 S	288,68	-68,42 N	106,25 N	174,67 E
(m) #MA	2,31 N	-6,58 S	338,41	-18,69 N	94,51 N	113,2 E

 MD = meridian distance (from MC if SA f SU  is diurnal or IC if Sa f  is nocturnal) – SA = semi-arc (if f is diurnal, SA f SU is D and all MD’s and SA’s are D, otherwise N – HA = horizontal distance (from the nearest horizon W or E for f SU and m (m) #MA)

Observe that at the time of death (corresponding to an arc of 2h 43, i.e. 7h18 LMC), on the one hand SU (357° of progressed domitude) is opposite to ALGOL (175° of domitude) and that the counter-parallel of MA is in conjunction with SU (35° of domitude radix)

We must take into account an important element: the ascensional difference (DA); it can be observed on the  graph in a dotted line (measured between the horizon and the axis of the pole). This is the difference between Right Ascension (AR) and Oblique Ascension (OA).This is the difference between Right Ascension (AR) and Oblique Ascension (OA). DA is always calculated in absolute value |DA| and it is added or subtracted from 90° (SA = 90° corresponds to a point on the equator cut by the horizon; depending on whether a star approaches or moves away from the line of horizon, SA is > 90° or < 90°, i,e, (+) depending on whether it is diurnal and northern ; or nocturnal and southern ; (-) depending on whether it is diurnal and southern ; or nocturnal and northern.

sin(DA) = -tan(φ)tan(δ)
φ = latitude 34,25 N
δ SU = -22,34 -
DA-SU = 16,25°
δ (m) #MA =-6,58 -
DA-(m) #MA =4,51°

We will first use the Placidus system of mundane directions. The simplest system is that of Choisnard-Fomalhaut. First you need to retrieve the data from the SA (semi-arc) and the DM (meridian distance) of the nocturnal point because the altitude of SU is -29,68°. important note: the SA and DM of the two points are always counted diurnal if the first point (here SU) is above the horizon even if the second is below. They are counted nightly if the first point (SU) is below the horizon regardless of the position of the second point.
For DMs, they are counted in AR from the diurnal meridian if the fixed point SU is diurnal, and from the nocturnal meridian if it is nocturnal.

nocturnal meridian MC = 357,1°
AR SU = 288,68°
AR (m) #MA = 338,41°

 = 106,25°
DM N  SU = -68,42°

For the  significator  (m) #MA altitude (h) =-57,39°. so :

 = 94,51°
DM N  (m) #MA = -18,69°

Then we compute Saf/DMf (so : SA f [ 106,25°] / DM f [ -68,42°])

Sa f / DM f =1,55

and the angle x = SAm x DM f/SA f, so : SA m [ 94,51°] x DM f [ -68,42°]/SA f [ 106,25°]

 x = 299,14°

We find the direction by DMm - x, so : DM m [ -18,69°] ± x [299,14]
We must now have regard to the double ± sign of the last expression; in the case where f (SU) and m ((m) #MA) are on either side of the meridian, the direction arc is obtained by taking the sum (instead of the difference) of the two quantities DMm and x. This is not the case here, so sign = (+)
the computation of the arc requires, depending on the case, a reduction of 360° (so arc modulo 360°)
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arc D =-42,17°
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in the technical sense, It is a direct direction but in the astrological sense, it is a true converse direction since it is an aspect considered as a promissor which goes towards the significator. ; so the m point is an aspect (here (m) #MA) and the f point is a planet or an axis, (here SU)

We can now compute the converse direction : point f is directed towards point m, i.e. the star is directed towards the aspect. This is where the problem of the orientation of the primum mobile arises because it is not concevable to rotate the local sphere in both directions… It does not seem convenient to postulate that the arc of direction is counted in the order of the signs of the zodiac (when it is direct, i.e. when one directs a promissor towards a significator): indeed, the ecliptic has nothing to do with a direction since this one depends only on the diurnal movement ( primum mobile). It is therefore otherwise that we must pass judgment on this.

That time, we compute Sa m / DM m (so : SA m [ 94,51°] / DM f [ -18,69°])

Sa m / DM m =0,59

and the angle x = SA f x DM m/SA m, so : SA f [ 106,25°] x DM m [ -18,69°] / SA m [ 94,51°]

x = -21,02°

We find the direction by DM f - x, so : DM f [ -68,42°] ± x [-21,02°]
We must now have regard to the double ± sign of the last expression; in the case where m ((m) #MA) and f (SU) are on either side of the meridian, the direction arc is obtained by taking the sum (instead of the difference) of the two quantities DM f and x. This is not the case here, so sign = (+)
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arc C =47,4°
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Now we can study the same direction with the Regiomontanus system. To obtain the arc of direction between two signifying points (planets in body, aspect versus planet, planet versus axis) one must find AO (oblique ascent) of f and of m, calculated under the pole of f.
The formulas to use can be found either in the Dictionnaire astrologique of Henri Joseph Gouchon (Dervy Livres, 1937) pp. 266-267, or in his Horoscope annuel simplifié (Dervy, 1973) p.181. Other formulas can be found in Les moyens de pronostic en astrologie, Max Duval (editions traditionnelles, 1986) and Domification et transits (Editions traditionnelles, 1985). We can also cite by André Boudineau : Les bases scientifiques de l’astrologie (Chacornac, 1937) These are references in French but there are many other references in English or German of a less obvious but equally valid use.

First, compute the ascensional difference under f (SU) : cot DAP f = (cot de f x cot lat) / in DM f ± cot DM f, i,e, :  cot (DAP f) = (Cot dec f[-22,34°] x Cot Lat [34,25°]) /sin DM f [68,42°] ± cot DM f  [68,42°]

DAPf = 163,83°

We find the pole of f (SU) by formula : tan(pole f) = sin (DAP f) x cot (dec f) i,e, tan(pole f) = tan f [13,27°] x cot f [-22,34°]

pole SU regio  =-29,19°

(1) We need now the DAP of m ((m) #MA) under the pole of f, sin (DAP m) = tan (pole f) x tan (DEC m), i,e, : (SU) : sin (DAPm/f) = tan [29,2°] x tan [-6,58°]

DAP m/f = -3,7°

then we find for the points located in the eastern part of the chart : AO f = AR f± DAP f ; sign (+) if Dec f boreal or sign (–) if Dec f Austral ; so : AO f SU = 301,95° and AO m = AR m ± DAP m ; idem for sign ; so  AO m(m) #MA = 342,1°

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arc D Regio = 40,15°
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We are now going to compute the converse Regiomontanus direction corresponding to the arc  f SU / p (m) #MA

First, compute the ascensional difference under m ((m) #MA) : cot DAPm = (cot dec m x cot lat)/sin DM m ± cot DM m, i,e, :  Cot(DAP m) = (Cot decm[-6,58°] x Cot Lat [34,25°]) / Sin DM f [161,31°] ± Cot DM m [-18,69°]

DAP m = 1,56°

We find the pole of m ((m) #MA) by formula : Tan(pole m) = Sin (DAP m) x Cot (dec m) i,e, Tan(pole m) = Sin m [178,66°] x Cot m [-6,58°]

pole (m) #MA regio  =-11,48°

We need now the DAP of f (SU) under the pole of m, Sin (DAP f) = Tan (pole m) x Tan (DEC f), i,e, : ((m) #MA) : Sin (DAP f/m) = Tan[11,48°] x Tan [-22,34°]

DAP f/m = -4,79°

then we find for the points located in the eastern part of the chart : AO m = AR m ± DAP m ; sign (+) if Dec m boreal or sign (–) if Dec m Austral ; so : AO m (m) #MA = 340° and AO f = AR f ± DAP f ; idem for sign ; so  AO f SU = 293,46°

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arc C Regio = -46,28°
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H.J. Gouchon [l’Horoscope Annuel simplifié, Dervy, 1973, p, 181-182 and Dictionnaire astrologique, p, 277, 1937-1942, Gouchon ed., 1975, Dervy, but be careful because in DAP's equation, the double sign ± was mistakenly replaced by the sign (-) ] advises to avoid errors, to always place the star A1 (for us f, i.e. SU) in the eastern houses; in fact it is enough to change the registration number of the house based on the transformation (IV-V-VI) -> (X-XI-XII) and (VII-VIII-IX) -> (I-II-III ) to adapt the double sign ± in the calculation of DAP f or DAP m; moreover, this sign must be reversed if |DM| > 90°.

For the Regiomontanus directions, there is another mode of computing, mentioned by Gouchon (Dictionnaire astrologique, op. cit., p. 276) and especially Martin Gansten (Primary directions, pp. 155-157, the Wessex Astrologer, 2009)
This method consists at computing first 3 auxiliary angles before  the pole. It then joins the other method. Contrary to what Gouchon says, I find it easier than the previous one because we avoid the double sign ± in the determination of DAP f.

So, initially, we have A => Tan f = tan dec f [-22,34°] / cos DM f [-68,42°]

A = -48,17°

Then : B = Lat [34,25°] + A [-48,17°]

B = -13,92°

And, Tang C = Cot DM f [-68,42°] x Cos B [-13,92°] / Cos A [-48,17°]

C = -29,93°

Then, we have Sin pole f = Cos C [-29,93°] x  Sin LG [34,25°]
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So, pole SU regio = 29,19°
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Now go back to (1)

For m (m) #MA; we have : A => Tan m = tan dec m [-6,58°] / cos DM m [-18,69°]

A = -6,94°

Then : B = Lat [34,25°] + A [-6,94°]

B = 27,31°

And, Tang C = Cot DM m [-18,69°] x Cos B [27,31°] / Cos A [-6,94°]

C = -69,29°

Then, we have Sin pole m = Cos C [-69,29°] x  Sin LG [34,25°]
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So, pole (m) #MA regio = 11,48°
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Now go back to (1)

 

This armillary sphere presents us with a true stereographic projection of the DIRECTION : (m) #MA conj SU
We see the superior meridian upper the pole 34,25° N LAT , the inferior meridian, and the other great circles : equator, ecliptic λ, latitude circle β, azimuth circle A and horary circle H
the zenith with colat 55,75° and the prime vertical
the horizon with ecliptic inclination of 44,05° and the ecliptic pole at 45,95°
the line Nord-Sud, as a circle, is the equinoctial colure ; the meridian circle can be considered as the solsticial colure (i,e, the equinoctial colure is a meridian passing through the equinoctial points ; and the solsticial colure is a meridian passing through the solsticial points). The colures therefore divide the apparent annual path of the Sun into four parts which determine the seasons,,,

Ascensional difference (DA) for f SU is = sin DA = -tan(lat [34,25]) x tan(dec f [-22,32])
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so DA f SU = 16,24°
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Ascensional difference (DA) for m (m) #MA is = sin DA = -tan(lat [34,25]) x tan(dec f [22,4])
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so DA m (m) #MA = 16,3°
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You see  also an almucantar circle for the mundane primary directions : actually the altitude of m (m) #MA = -29,68° ; it is therefore almost equal to the altitude of the su and therefore m and f are in mundane conjunction because Δ alt <2° (0,78°), This altitude corresponds to that of point f SU (alt f = -29,68), assumed to have remained fixed during the displacement of the diurnal movement.
note that if the m point is a counter parallel, it is retrograde (and it is not a zodiacal aspect because one use declination to compute mundane parallel),
mundane parallels are taken from the angles of a figure in the same way as zodiacal parallels are taken from the equator, and are measured by the semiarcs of the planets, placidus was the inventor of mundane parallels and he appears to have relied much on their efficacy
We can see too two or three parallels of declination ; for point m (m) #MA with dashed line (between equator and equinoctial colure) to design the m DA (see above) ; for point f SU (idem) and for a star (Algol i,e, β Persei or another if present in the sky path of the natal chart),
Then we find the index for rising, transit and setting the two points f and m.